Given that the radius of the circular path is r = 142 m and the coefficient of the friction is

The condition for the car to travel safely is
Frictional force = centrifugal force

Here, m is the mass of the car and the acceleration due to gravity is g = 9.8 m/s^2.
v is the maximum speed of the car.
![\begin{gathered} v=\sqrt[]{ugr} \\ =\sqrt[]{1.07*9.8*142} \\ =38.58\text{ m/s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/high-school/1zpq3708qry3zw1bcqct6t0r2heebo2cvs.png)