Given that the radius of the circular path is r = 142 m and the coefficient of the friction is
![\mu=1.07](https://img.qammunity.org/2023/formulas/physics/high-school/vuitng7mev9czz9nqs97pys74jb6eqd6ad.png)
The condition for the car to travel safely is
Frictional force = centrifugal force
![\mu mg=(mv^2)/(r)](https://img.qammunity.org/2023/formulas/physics/high-school/6zkkaemst2256qjh1c87qcr2otjwiiydg2.png)
Here, m is the mass of the car and the acceleration due to gravity is g = 9.8 m/s^2.
v is the maximum speed of the car.
![\begin{gathered} v=\sqrt[]{ugr} \\ =\sqrt[]{1.07*9.8*142} \\ =38.58\text{ m/s} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/high-school/1zpq3708qry3zw1bcqct6t0r2heebo2cvs.png)