Question

4.A gas occupies 8.7L at a temperature of 29.0°c. What is thevolume at 133°C? (Charles Law)

Answer 1

11.7L

Explanations

According to Charles law, the volume of a given mass of gas is directly proportional to its temperature provided that the pressure is constant. Mathematically;

`\begin{gathered} v\alpha T \\ v=kT \\ k=(v_1)/(T_1)=(v_2)/(T_2) \end{gathered}`

where:

• v1 and v2 are the ,initial and final ,volume

,

• T1 and T2 are the, initial and final, temperature

Given the following parameters

v1 = 8.7L

T1 = 29.0°C = 29 + 273

T1 = 302K

T2 = 133+ 273 = 406K

Substitute the given parameters into the formula

`\begin{gathered} v_2=(v_1T_2)/(T_1) \\ v_2=(8.7L*406)/(302) \\ v_2=(3532.2)/(302) \\ v_2=11.7L \end{gathered}`

Hence the volume of the gas at 133°C is 11.7L