120k views
3 votes
write the equation of the line that is perpendicular to the graph of y=3/4x-3, and whose y-intercept is -8

User AndroC
by
8.4k points

1 Answer

3 votes

write the equation of the line that is perpendicular to the graph of y=3/4x-3, and whose y-intercept is -8

step 1

Find the slope of the given line

y=(3/4)x-3

the slope is m=3/4

step 2

Find the slope of the perpendicular line

REmember that

If two lines are perpendicular, then the product of their slopes is equal to -1 (inverse reciprocal)

so

the slope of the perpendicular line is

m=-4/3

step 3

Find the equation of the line

we have

m=-4/3

y-intercept is -8

so

b=-8

y=mx+b

substitute

y=-(4/3)x-8

Part 2

write an equation of the line that is parallel to the graph of y=-4x-9, and whose y-intercept is 3

step 1

Find the slope of the given line

y=-4x-9

the lope is m=-4

step 2

Find the slope of the parallel line

Remember that

If two lines are parallel, then their slopes are the same

so

the slope of the parallel line is m=-4

step 3

Find the equation of the line in slope intercept form

y=mx+b

we ahve

m=-4

b=3

substitute

y=-4x+3

User Rolf Bartstra
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories