Question

For the function f(x) = x2 + 2x - 15 solve the following.f(x) = 0

Answer 1

Given:

`f\mleft(x\mright)=x^2+2x-15`

To find: The value of x when

`f(x)=0`

Step-by-step explanation:

Since,

`f(x)=0`

We can write it as,

`\begin{gathered} x^2+2x-15=0 \\ x^2+5x-3x-15=0 \\ x(x^{}+5)-3(x-5)=0 \\ (x+5)(x-3)=0 \\ x=-5,3 \end{gathered}`

Hence, the solution is x = -5, and 3.

Final answer: The solution is,

`\mleft\lbrace-5,3\mright\rbrace`