The pH of this solution is 0.207
Hello
To solve this question, we need to use the formula of solving pH of a solution from hydrogen or hydronium ion.
![\begin{gathered} pH=-\text{log\lbrack{}H}_3O^+\rbrack \\ \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/q94p64v1kjclslzju3u8frdoyig3p4h7af.png)
Now, we would proceed to substitute the given value and solve for it.
![\begin{gathered} pH=-\log \lbrack0.62\rbrack \\ pH=0.207 \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/7imsaeiwq2c62245rxdpy6rov9b90j6mx2.png)
NB: we did not use the value of temperature because it is not needed in this solution.
From the calculation above, the pH of this solution is 0.207