Question

A bag contains 6 green balls and 4 yellow balls. What is the probability that two balls picked randomly are both of the same color?

Answer 1

Given:

The number of green balls is G = 6.

The numer of yellow balls is Y = 4.

Step-by-step explanation:

Determine the total number of balls.

`\begin{gathered} T=6+4 \\ =10 \end{gathered}`

Determine the probability for both selected balls to be green.

`\begin{gathered} P(G)=(6)/(10)\cdot(5)/(9) \\ =(15)/(45) \end{gathered}`

Determine the probability for selected balls to be yellow.

`\begin{gathered} P(Y)=(4)/(10)\cdot(3)/(9) \\ =(6)/(45) \end{gathered}`

Determine the probability for both selected balls to be of same colour.

`\begin{gathered} P=P(G)+P(Y) \\ =(15)/(45)+(6)/(45) \\ =(21)/(45) \\ =(7)/(15) \end{gathered}`