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Find the answer to this question.

Find the answer to this question.-example-1
User Don Shrout
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6 votes

Check the picture below.

so let's get "h" and thus we can get the area of the trapezoid.


\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies √(c^2 - a^2)=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ √(17^2 - 8^2)=h\implies √(225)=h\implies 15=h \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h~~=height\\ a,b=\stackrel{parallel~sides}{bases~\hfill }\\[-0.5em] \hrulefill\\ h=15\\ a=12\\ b=20 \end{cases}\implies A=\cfrac{15(12+20)}{2}\implies A=240~m^2

well, for that, that'd be 2 can plus some more for the remaining 40 m², so I'd think 3 cans will do it,


\pounds 19.75\cdot \stackrel{cans}{3}\implies \text{\LARGE \pounds 59.25}

Find the answer to this question.-example-1
User MAZux
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