Question

A hair dryer draws 6.0 A when plugged into a 120-V line. (a) What is its resistance? (b) How much charge passes through it in 15 min?

Answer 1

We will have the following:

a)

`R=(120V)/(6A)\Rightarrow R=20\Omega`

b)

`Q=(6A)(15min\ast(60s)/(1min))\Rightarrow Q=5400W`

So, the charge is 5400 W in 15 minutes.