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Let's say you have a bag with 12 cherries, 4 of the cherries are sweet and 8 are sour. If you pick a cherry atrandom, what is the probability that it will be sweet? Write your answer as a reduced fraction.Pot)

User Greg Elin
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1 Answer

3 votes

1) A rolled die has just 6 outcomes; from 1 to 6


\text{Probability = }\frac{number\text{ of required events}}{nu\text{mber of total events}}

Number of total events for a die = 6


\begin{gathered} a)\text{ p(6) } \\ \text{for this the number of required events = 1 because there can and there is only one six showing at a time} \\ p(6)\text{ =}(1)/(6) \end{gathered}
\begin{gathered} b)\text{ p(even)} \\ Here\text{ number of total events are 1,2,3,4,5 and 6} \\ \text{The number of even numbers = 3} \\ \\ p(\text{even) =}(3)/(6)=(1)/(2) \end{gathered}
\begin{gathered} c)p(\text{greater than 1)} \\ \text{Here total number of outcomes are 1,2,3,4,5 and 6} \\ \text{numbers greater than 1 are 2,3,4,5 and 6}\ldots..\text{ Th}ere\text{ are 5 of them} \\ \text{Hence} \\ p(\text{greater than 1) =}(5)/(6) \end{gathered}
\begin{gathered} 2)\text{ Total number of cherries = 12} \\ p(\text{sweet) =}\frac{number\text{ of sw}eet\text{ cherries}}{Total\text{number of cherries}} \\ \text{number of swe}et\text{ cherries= 4} \\ p(\text{sweet) =}(4)/(12)=(1)/(3) \end{gathered}

User Herzog
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