SOLUTION
Write out the polynomial given
The first group of the expresion is

GCE is x²
For the second group, we have

The GCE for the secod group is 25
To factorise completely, we have

Then by simplification, we have

Then factors are (3x +4)(x²+ 25)
To find the real root, we equate each of the factors to zero, hence

Thus
![\begin{gathered} (3x)/(3)=-(4)/(3) \\ x=-(4)/(3)\text{ is a real root } \\ or\text{ } \\ x^2=-25 \\ \text{take square root} \\ x=\pm_{}\sqrt[]{-25}\text{ not a real root} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/aiabiy8oq5wflbxu6xvcc0g1esht5eze9k.png)
Therefore, since the root of -25 is a complex number,
The only real root is x = -4/3