Question

A container of an ideal gas is at STP. It holds 2.90mol of gas.What is the volume of the gas?L

Answer 1

Step-by-step explanation:

We are given: 2.90mol of ideal gas

At STP: Pressure = 1 atm

: Temperature = 273.15 K

: R = 0.08205 L.atm/mol.K

Using the ideal gas law:

`\begin{gathered} PV\text{ = nRT} \\ \\ \therefore V\text{ = }(nRT)/(P)\text{ = }\frac{2.9\text{ }*0.08205*273.15}{1}\text{ = 64.99 L} \end{gathered}`

Answer:

V = 64.99 L