Question

At the Avonlea Country Club, 54% of the members play bridge and swim, and 89% of the members play bridge. If a member is selected at random, what is the probability that the members swims, given that the member plays bridge?

Answer 1

`P(S|B)=0.61`

Step-by-step explanation

We are given that 54% of the members at the club play bridge and swim, and 89% of the members play bridge.

`\begin{gathered} P(\text{BnS)}=0.54 \\ P(B)=0.89 \end{gathered}`

To find the probability that the member swims given that he/she plays bridge, we have to apply conditional probability.

The probability that the member swims given that he/she plays bridge is gotten by dividing the probability that the member plays bridge and swims by the probability that the member plays bridge:

`\begin{gathered} P(S|B)=(P(B\cap S))/(P(B)) \\ \Rightarrow P(S|B)=(0.54)/(0.89) \\ P(S|B)=0.61 \end{gathered}`

That is the answer.