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If Adam rides his bicycle in a straight line for 21 min with an average velocity of 9.98 km/h south how far has he ridden

User Shj
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1 Answer

5 votes

Given data:

* The time taken by the Adam is,


\begin{gathered} t=21\text{ min} \\ t=1260\text{ s} \end{gathered}

* The average velocity of the Adam is,


\begin{gathered} v=9.98kmh^(-1) \\ v=9.98*(10^3)/(60*60)ms^(-1) \\ v=2.77ms^(-1) \end{gathered}

Solution:

The distance traveled by the Adam is,


\begin{gathered} d=vt \\ d=2.77*1260 \\ d=3490.2\text{ m} \\ d=3.49\text{ km} \end{gathered}

Thus, the distance traveled by the Adam on the bicycle is 3.49 km.

User ThisIsNoZaku
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