1 Answer

Joshualan · Answer 1 · 2023-05-17T23:32:58+0000

Given data:

* The value of angular velocity is,

$\omega=1.3\text{ rad/s}$

Solution:

(a). The time period of the oscillation in terms of the angular velocity is,

$T=(2\pi)/(\omega)$

Substituting the known values,

$\begin{gathered} T=(2\pi)/(1.3) \\ T=4.83\text{ s} \end{gathered}$

Thus, the time period of oscillation is 4.83 s.

(b). The frequency of the oscillation in terms of the time period is,

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