What is the vertex for the graph of y– 4 = - (x+1)^2??O A. (4,-1)O B. (1,-4)O c. (-1,4)O D. (-4,1)

Question

asked Feb 11, 2023 113k views

1 Answer

Delton · Answer 1 · 2023-02-17T15:39:04+0000

The equiation of parabola in vertex form is:

$y\text{ = a}\cdot(x-h)^2\text{ + k}$

where (h, k) are the coordinates of the vertex and a is a constant. In our case we have:

add 4 to both sides:

$y\text{ -4 +4 = -}(x+1)^2\text{ + 4}$

Resolving:

$y=-(x+1)^2\text{ + 4}$

Therefore we already have it in the vertex form and we have to:

$\begin{gathered} h\text{ = -1 } \\ k\text{ = 4} \end{gathered}$

Therefore the answer is c. (-1, 4)