Given:
Principal (P)=$200
Rate of interest (r) =4%
time (t)=30 years
Number of times compounded per year(n) = 12
Required- the amount.
Step-by-step explanation:
First, we change the rate of interest in decimal by removing the "%" sign and dividing by 100 as:
![\begin{gathered} r=4\% \\ \\ =(4)/(100) \\ \\ =0.04 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/enjqc5io98ij2xnze1iik80lr5nhmra923.png)
Now, the formula for finding the amount is:
![A=P(1+(r)/(n))^(nt)](https://img.qammunity.org/2023/formulas/mathematics/high-school/39foo2gerf9tf1ffk32zwshrn339mz02kv.png)
Put the given values in the formula, we get:
![A=200(1+(0.04)/(12))^(12*30)](https://img.qammunity.org/2023/formulas/mathematics/college/xguv3k4ckk7gjrkieysa2mwu0frmkfmg07.png)
Solving further, we get:
![undefined]()