Question

If there are 1.1 moles of SeCl6 how many moles of Cl2 will be produced? Use up to one decimal point

Answer 1

There are 3.3 moles of Cl2 in 1.1 moles of SeCl6

Step-by-step explanation

Given that

The number of moles of SeCl6 is 1.1 moles

Firstly, write a balanced equation of the reaction

`\text{ SeCl}_6\text{ }\rightarrow\text{ Se + 3Cl}_2`

In the reaction above, 1 mole SeCl6 gives 3 moles Cl2

Let x be the number of moles of Cl2

`\begin{gathered} \text{ 1 mole SeCl}_6\text{ }\rightarrow\text{ 3 moles Cl}_2 \\ \text{ 1.1 mole SeCl}_6\text{ }\rightarrow\text{ x moles Cl}_2 \\ \text{ cross multiply} \\ \text{ 1 mole SeCl}_6*\text{ x moles Cl}_2\text{ = 1.1 mole SeCl}_6\text{ }*\text{ 3 moles Cl}_2 \\ \text{ Isolate x } \\ \text{ x = }\frac{1.1moles\cancel{SeCl_6}*\text{ 3 moles Cl}_2}{1mole\cancel{SeCl_6}} \\ \\ \text{ x = 1.1 }*\text{ 3} \\ \text{ x = 3.3 moles} \end{gathered}`

Therefore, there are 3.3 moles of Cl2 in 1.1 moles of SeCl6