Question

Hi, I need help with this problem please. No explanations/steps required. Just need the final answer

Answer 1

To simplify the expression we fist need to express each trigonometric function in terms of sines and cosines; to do this we need to remember that:

`\begin{gathered} \sec x=(1)/(\cos x) \\ \csc x=(1)/(\sin x) \end{gathered}`

With this in mind we have:

`\begin{gathered} (\csc x)/(\sec x)=((1)/(\sin x))/((1)/(\cos x)) \\ =(\cos x)/(\sin x) \end{gathered}`

Finally we need to remember that:

`\cot x=(\cos x)/(\sin x)`

Therefore, we have that:

`(\csc x)/(\sec x)=\cot x`