Question

AABC is isosceles.mZA = 3x + 40 and mZC = x + 50BAmZA= [ ? 1°

Answer 1

The value of the angle A is 55°

Explanation:

Angles opposite equal sides are angles that are also equal.

Therefore, in this case A and C are equal angles, therefore we can do the following equation:

`\begin{gathered} A=C \\ 3x+40=x+50 \end{gathered}`

Solving for x:

`\begin{gathered} 3x-x=50-40 \\ 2x=10 \\ x=(10)/(2) \\ x=5 \end{gathered}`

Now we replace the value of x, in A and we are left with:

`\begin{gathered} A=3\cdot5+40 \\ A=15+40 \\ A=55 \end{gathered}`