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6. What would be the concentration of a solution formed when 1.00 g of NaCl are dissolved in water to make100 mL of solution?

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To find the concentration we can do it in terms of molarity. Molarity is a way of expressing the concentration of a solute in a solution, it is expressed with the term M and can be described by the following equation:


Molarity=(MolesSolute)/(Lsolution)

So first we must find the moles of NaCl present in 1.00 grams, the moles of NaCl will be:


\begin{gathered} molNaCl=givengNaCl*(1molNaCl)/(MolarMass,gNaCl) \\ molNaCl=1.00gNaCl*(1molNaCl)/(58.44gNaCl)=0.017molNaCl \end{gathered}

So, the molarity of the solution will be:


Molarity=(0.017molNaCl)/(0.100Lsolution)=0.17M

Answer: The concentration of the solution in molarity will be 0.17M

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