Question

6. What would be the concentration of a solution formed when 1.00 g of NaCl are dissolved in water to make100 mL of solution?

Answer 1

To find the concentration we can do it in terms of molarity. Molarity is a way of expressing the concentration of a solute in a solution, it is expressed with the term M and can be described by the following equation:

`Molarity=(MolesSolute)/(Lsolution)`

So first we must find the moles of NaCl present in 1.00 grams, the moles of NaCl will be:

`\begin{gathered} molNaCl=givengNaCl*(1molNaCl)/(MolarMass,gNaCl) \\ molNaCl=1.00gNaCl*(1molNaCl)/(58.44gNaCl)=0.017molNaCl \end{gathered}`

So, the molarity of the solution will be:

`Molarity=(0.017molNaCl)/(0.100Lsolution)=0.17M`

Answer: The concentration of the solution in molarity will be 0.17M