Question

NEED THIS SOLVED ASAP PLS HELP ME!!!

Answer 1

Explanation:

`3x ^(2) - 6x - 4 = 0`

`by \: quadratic \: formula`

`(-b±√(b²-4ac))/(2a)`

`- ( - 6)±√( - 6²-4(3)( - 4) /(2 * 3)`

`(6±√(36 + 48)/(6)`

`(6±√(84)/(6)`

`(6±2√21)/6`

`2(3±√21)/6`

`3±√21/3`

`let \: \alpha \: and \: \beta \: be \: two \: roots \: .`

`3 + √(21) /3`

`3 + 4.58/3`

`7.48/3`

`2.52`

`and \: second \: root \: = 3 - √(21) /3`

`3 - 4.58/3`

`- 1.58/3`

`- 0.52`

`so \ \: alpha = 2.52 \: and \: \beta = - 0.52`

Answer 2

x= 1 ±√21/3

x= 2.52753

x= - 0.527525

Explanation:

-(-6) ±√-6² - 4 (3) (-4) / 2(3)

6±√36 -(-48) / 6

6±√84/6

6±2√21/6

6/6 ±2√21/6

1±√21/3

1+ √21/3 = 2.52753

1-√21/3= - 0.527525