Question

i need physics help.The charge of an electron is - 1.6 x 10^ -19 C.Show that there are about 3 x 10^18 electrons in 5 x 10^8 nC of charge.

Answer 1

Given:

Charge of an electron = -1.6 x 10⁻¹⁹ C

Let's show that there are about 3 x 10¹⁸ electrons in 5 x 10⁸ nC of charge.

Using the given charge of an electron, to find the number of electrons in 5 x 10⁸ nC of charge, we have:

`(5*10^8*10^(-9))/(1.6*10^(-19))=3*10^(18)`

Now, let's prove this equation is true.

Simplify the left side:

`\begin{gathered} (5*10^8*10^(-9))/(1.6*10^(-19)) \\ \\ =(5*10^(-1))/(1.6*10^(-19)) \\ \\ =3.125*10^(-18)\text{ electrons} \end{gathered}`

We can see the number of electrons calculated is equivalent to the number of electrons given.

Therefore, we have shown that there are about 3 x 10¹⁸ electrons in 5 x 10⁸ nC of charge.

ANSWER:

Number of electrons = 3.125 x 10¹⁸ electrons