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Square ABCD has vertices at A(-1, 2) and B(3, -3). What is the slope of segment BC?

Square ABCD has vertices at A(-1, 2) and B(3, -3). What is the slope of segment BC?
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1 vote
Square ABCD has vertices at A(-1, 2) and B(3, -3).
What is the slope of segment BC?

User Dekajoo
by
8.5k points

1 Answer

5 votes

Answer:

BC=OB-OA

BC=(3/-3) - (-1/2)

BC= -1-3/2--3

-4/5=BC

User Aborruso
by
8.0k points
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