Question

How would I figure out 4 could you draw it out so I could understand betters it’s my first day learning this

Answer 1

Question 4

The sketch of the isosceles right triangle is given below

For an isosceles right triangle, the two legs are equal

So we will get the value x as follow

`\begin{gathered} x^2+x^2=8^2 \\ 2x^2=8^2 \\ 2x^2=64 \\ x^2=32 \\ x=4\sqrt[]{2} \end{gathered}`

The perimeter of the triangle can be obtained as follow

The perimeter is simply the sum of all the sides of the triangle

`\begin{gathered} \text{Perimeter}=x+x+8 \\ \text{Perimeter}=4\sqrt[]{2}+4\sqrt[]{2}+8=8\sqrt[]{2}+8 \\ \text{Perimeter}=8\sqrt[]{2}+8 \\ \text{Perimeter}=8(\sqrt[]{2}+1) \\ \text{Perimeter}=19.31\text{ units} \end{gathered}`

To get the area of the triangle

we will use the formula

`\begin{gathered} \text{Area}=(1)/(2)* base*\text{height} \\ \text{Area}=(1)/(2)*4\sqrt[]{2}*4\sqrt[]{2} \\ \text{Area}=2\sqrt[]{2}*4\sqrt[]{2} \\ \text{Area}=2*4*2 \\ \text{Area}=16 \end{gathered}`

The area of the triangle is 16 square units