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Find the area of a triangle ABC when c = 15 m, a = 20 meters, and b = 10 meters.

Find the area of a triangle ABC when c = 15 m, a = 20 meters, and b = 10 meters.-example-1

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Recall Heron's Formula to find the area of a triangle with sides a, b and c.

We define a new quantity s given by:


s=(a+b+c)/(2)

Then, the area of the triangle is given by the formula:


A=√(s(s-a)(s-b)(s-c))

For a=20, b=10 and c=15 we have:


s=(20+10+15)/(2)=22.5

Then, the area of the triangle is:


\begin{gathered} A=√(22.5(22.5-20)(22.5-10)(22.5-15)) \\ =√(22.5(2.5)(12.5)(7.5)) \\ =(75√(15))/(4) \\ =72.61843774... \\ \approx72.6 \end{gathered}

Therefore, the exact answer is:


A=(75√(15))/(4)

And the approximate area of the triangle ABC when c=15m, a=20m and b=10m is 72.6 m^2.

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