230k views
1 vote
A line passes through(1,-5) and (-3,7) write an equation for the line in point-slope form Rewrite the equation in slope-intercept form A. Y-5=1/3(x+1) ; y =1/3x + 16/3 B. Y+5=-3(x-1); y=-3x-2 C. Y-1=1/3(x+5);y=-1/3x+3/8 D. Y-5=3(x-1);y=3x+8

A line passes through(1,-5) and (-3,7) write an equation for the line in point-slope-example-1
User Alex Gill
by
7.8k points

1 Answer

6 votes

Step 1: Concept

Write the formula for the equation of a line in terms of point-slope form

and in slope-intercept form.


\begin{gathered} Pi\text{ont slope form is given below} \\ y-y_1=m(x-x_1) \\ \text{Slope}-\text{intercept form} \\ y\text{ = mx + c} \\ m\text{ = }(y_2-y_1)/(x_2-x_1) \\ \end{gathered}

Where

m = slope

c = intercept

Step 2: Represent the coordinates


\begin{gathered} (x_1,y_1\text{ ) = (1, -5)} \\ (x_2,y_2\text{ ) = ( -3, 7)} \end{gathered}

Step 3: Find the slope, using slope formula.


\begin{gathered} m\text{ = slope} \\ \text{m = }(y_2-y_1)/(x_2-x_1) \\ m\text{ = }\frac{7\text{ -(-5)}}{-3\text{ -1}} \\ m\text{ = }\frac{7\text{ + 5}}{-4} \\ m\text{ = }(12)/(-4) \\ m\text{ = -3} \end{gathered}

Step 4: Write an equation for the line in point-slope form.


\begin{gathered} \text{y - y}_1=m(x-x_1) \\ y\text{ -(-5) = -3(x - 1)} \\ \text{y + 5 = -3(x - 1)} \end{gathered}

Step 5: Simplify the equation in 4 to write the equation in slope-intercept form.

y + 5 = -3(x - 1)

y + 5 = -3x + 3

y = -3x + 3 - 5

y = -3x - 2

Final answer

Option B

y + 5 = -3(x - 1)

y = -3x - 2

User Thum Choon Tat
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories