Question

Solve quadratic formulax^2-4x+3=0

Answer 1

The general formula for a equation of the form:

`ax^2+bx+c=0`

is:

`x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

In this case we notice that a=1, b=-4 and c=3. Plugging this values in the general formula we get:

`\begin{gathered} x=\frac{-(-4)\pm\sqrt[]{(-4)^2-4(1)(3)}}{2(1)} \\ =\frac{4\pm\sqrt[]{16-12}}{2} \\ =\frac{4\pm\sqrt[]{4}}{2} \\ =(4\pm2)/(2) \end{gathered}`

then:

`x_1=(4+2)/(2)=(6)/(2)=3`

and

`x_2=(4-2)/(2)=(2)/(2)=1`

Therefore, x=3 or x=1.