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We have to write the equation of the line using y=mx+b passing through the points (6,2) and (2,4)

User Umitu
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The general equation of line passes through point (x_1,y_1) and (x_2,y_2) is,


y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)

Determine the equation of line passes through point (6,2) and (2,4).


\begin{gathered} y-2=(4-2)/(2-6)(x-6) \\ y-2=(2)/(-4)(x-6) \\ y=-(1)/(2)x+3+2 \\ =-(1)/(2)x+5 \end{gathered}

So equation of line is y = -1/2x + 5.

User Tirdad Abbasi
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