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Use the law of sines to solve the triangle if possible

Use the law of sines to solve the triangle if possible-example-1

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The Sine rule formula is,


(a)/(sinA)=(b)/(sinB)=(c)/(sinC)

Given:


\begin{gathered} a=13.9in \\ A=83^0 \\ b=18.3in \\ B=? \end{gathered}

Let us solve for solve for the measure of angle B


(13.9)/(sin83^0)=(18.3)/(sinB)

Therefore,


\begin{gathered} sinB=(18.3* sin83^0)/(13.9)=1.30673342266 \\ \therefore B=sin^(-1)(1.30673342266)=No\text{ solution} \end{gathered}

Hence, there are no possible solutions for this triangle (OPTION C).

User Ahmaad
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