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What is the total number of moles of products formed when 1.20 moles of ammonia reacts? 4NH3+5O2 --> 4NO+6H2O

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Step-by-step explanation:

Step 1 - We need to rewrite the equation here:

4NH3+5O2 --> 4NO+6H2O

The ratio between ammonia (NH3) and the products are:

NH3 and NO:

4:4

NH3 and H2O:

6 H2O

So if we have 1.2 moles of ammonia:

1.2 moles of NH3 ---- x moles of NO

4 moles of NH3 ---- 4 moles of NO

x = 1.2 moles of NO

1.2 moles of NH3 --- x moles of H2O

4 moles of NH3 --- 6 moles of H2O

4x = 7.2

x = 7.2/4

x = 1.8 moles of H2O.

Answer: The total number of moles of products formed is 1.2 moles of NO and 1.8 moles of H2O.

User Ricky Levi
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