Question

6. Examine the two-way frequency table below.Gold Medals Silver Medals Bronze MedalsUSA 201842Spain 2511France 192726Based on the data in the two-way frequency table, what is the probability that a randomly selected player won a bronze medal given that the player represented Spain?22.4%24.4%13.995.5%PREVIOURPREVIOUS6 ofNEXTREVIEWSALSion outINTL

Answer 1

From the table, we can get the total number of players that took part in the games.

See the new table below;

From the table, we got the sum of players from each country, and also the sum of medals won by each player. This gave us a total of 201 when we calculate the total medals collected or the total from all the countries. Hence, the name two-way.

From the table, the number of Spain players that won bronze is 11, hence, the probability is;

`\begin{gathered} \text{Probability = }\frac{n\text{umber of required outcome}}{n\text{ umber of total possible outcomes}} \\ P(\text{Spain player with bronze)= }\frac{n\text{ umber of Spain player that won bronze}}{\text{total n umber of players}} \\ =\text{ }(11)/(201) \\ =0.0547 \\ \text{Taking this to percentage, we have it to be 0.0547 x 100} \\ =5.47 \\ =5.5 \end{gathered}`

Therefore, the probability of selecting a Spain player that won a bronze medal at random is 5.5%