Question

In a circle with radius 0.9, an angle intercepts an arc of length 3.6. Find the angle inradians to the nearest tenth.

Answer 1

Given the question on the question tab;

`\begin{gathered} radius\text{ r=0.9} \\ angle\text{ }\theta=? \\ Length\text{ of arc=3.6} \end{gathered}`
`\begin{gathered} Length\text{ of arc =}\theta r \\ 3.6=0.9\theta \\ \theta=(3.6)/(0.9) \\ \theta=4.0 \end{gathered}`

The angle is 4.0