Question

Which equation can be used to find the solution of (1/4)y+1=64 ? −y−1=3y−1=3−y+1=3y + 1 = 3

Answer 1

`((1)/(4))^(y+1)=64`

1/4 and 64 can be expressed as follows:

`\begin{gathered} (1)/(4)=4^(-1) \\ 64=4^3 \end{gathered}`

Substituting into the equation:

`\begin{gathered} (4^(-1))^(y+1)=4^3 \\ 4^((-1)(y+1))=4^3 \\ 4^(-y-1)=4^3 \\ -y-1=3 \end{gathered}`