Question

I need help to find the area of each sector. I will send the exercise

Answer 1

The area of the circular sector is given by:

`\begin{gathered} A=(r^2\theta)/(2) \\ where\colon \\ r=radius=17mi \\ \theta=angle=(2\pi)/(3) \\ \end{gathered}`

Therefore:

`\begin{gathered} A=((17^2)(2\pi)/(3))/(2) \\ A=(289\pi)/(3)\approx302.64 \end{gathered}`