Step-by-step explanation:
We are given the linear equation;
![y-4=3(x+1)](https://img.qammunity.org/2023/formulas/mathematics/college/yg9cwdz92cw410xk0rpd2qxrdxmaivea4t.png)
To graph this equation, we would begin by re-writing the equation in the slope-intercept form, which is;
![y=mx+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/smsb8cbft03lwblmi49nf2l6jby2ofxzws.png)
To do this, we first expand the parenthesis;
![y-4=3x+3](https://img.qammunity.org/2023/formulas/mathematics/college/q5r8ln27afenyi1gjs8zssjf8kkig629zt.png)
Next we add 4 to both sides;
![y-4+4=3x+3+4](https://img.qammunity.org/2023/formulas/mathematics/college/bnuy6ei2xkp73f7aaocxzgo1mllb7xf9vl.png)
![y=3x+7](https://img.qammunity.org/2023/formulas/mathematics/high-school/xkjdnqte7iot06nbbo99b6hcskssywr45c.png)
We can now begin to plot the various points on the line. Starting from, x = -2 we would have;
![\begin{gathered} x=-2: \\ y=3(-2)+7 \\ y=-6+7 \\ y=1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/eq0r2mx1sa6gr1adigegt14vhdrlwd5wo5.png)
We can now go on and plot other points depending on the limit imposed by the graph page.
However, what we have here shows the coordinates from which we may begin;
ANSWER:
![\begin{gathered} (-2,1) \\ That\text{ is;} \\ x=-2,y=1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/xn8iuz9s9wsk4dr3tyd9klzlwlbs8uppsi.png)