49.8k views
2 votes
Statistics and probil

User StefanP
by
8.6k points

1 Answer

2 votes

we know that

Minimum value=838

Maximum value=1443

Difference=1443-838=605

we have that

Lower Class Limit Upper-Class Limit

838 838+x

838+x 838+2x

838+2x 838+3x

838+3x 838+4x

838+4x 838+5x

838+5x 838+6x=1443

Find out the value of x

838+6x=1443

6x=1443-838

6x=605

x=100.83

therefore

the answer is

Lower Class Limit Upper-Class Limit

838 838+100.83=938.83

938.83 1039.66

1039.66 1140.49

1140.49 1241.32

1241.32 1342.15

1342.15 1443

Find out the frequency for each class

838-938.83 ----> (838,842) ---------> frequency=2 ok

938.83- 1039.66 -----> (945,1034,1025) --------> frequency=3 ok

1039.66-1140.49 -----> (1124,1136,1057,1130) ----> frequency=4 ok

1140.49-1241.32 -----> (1184) ----> frequency=1 ok

1241.32-1342.15 ----> (1247, 1249,1256) -----> frequency=3 ok

1342.15- 1443 -----> (1352,1439,1439,1368,1381,1342,1395) -----> frequency=7

User Cliff Harris
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories