Answer:
14.45 g of O₂.
Step-by-step explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2KClO₃ —> 2KCl + 3O₂
Next, we shall determine the mass of KClO₃ that decomposed and the mass of O₂ produced from the balanced equation. This can be obtained as follow:
Molar mass of KClO₃ = 39 + 35.5 + (16×3)
= 39 + 35.5 + 48
= 122.5 g/mol
Mass of KClO₃ from the balanced equation = 2 × 122.5 = 245 g
Molar mass of O₂ = 2 ×16 = 32 g/mol
Mass of O₂ from the balanced equation = 3 × 32 = 96 g
SUMMARY:
From the balanced equation above,
245 g of KClO₃ decomposed to produce 96 g of O₂.
Finally, we shall determine the mass of O₂ produced by heating 36.89 g of KClO₃. This can be obtained as follow:
From the balanced equation above,
245 g of KClO₃ decomposed to produce 96 g of O₂.
Therefore, 36.89 g of KClO₃ will decompose to produce =
(36.89 × 96)/245 = 14.45 g of O₂
Thus, 14.45 g of O₂ were obtained from the reaction.