Question

[OH﹘] = 6.5 x 10-5Mfind the pH and pOH

Answer 1

pH = 9.81

pOH = 4.19

Explanations:

The formula for calculating the pOH of a solution is given as:

`pOH=-log[OH^-]`

Given the following parameters

`[OH^-]=6.5*10^(-5)M`

Substitute

`\begin{gathered} pOH=-log(6.5*10^(-5)) \\ pOH=-(-4.19) \\ pOH=4.19 \end{gathered}`

Determine the pH of the solution

`\begin{gathered} pH+pOH=14 \\ pH=14-pOH \\ pH=14-4.19 \\ pH=9.81 \end{gathered}`

Therefore the pH and pOH are 9.81 and 4.19 respectively