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1 vote
State if the give binomial is a factor of the given polynomial
(9x ^(3) + 57x^(2) + 21x + 24) / (x + 6)

User Birnbaum
by
8.2k points

1 Answer

2 votes

We want to find out if (x+6) is a factor of the polynomial


9x^3+57x^2+21x+24

In order to find this, we can use the factor theorem.

If we have a polynomial f(x) and want to find if (x-a) is a factor of this polynomial, we plug in x = a into the function and if we get 0, (x-a) is a factor(!)

Now, let's plug in:

x = -6 into the polynomial and see if we get a 0 or not.

Steps shown below:


\begin{gathered} 9x^3+57x^2+21x+24 \\ 9(-6)^3+57(-6)^2+21(-6)+24 \\ =-1944+2052-126+24 \\ =6 \end{gathered}

Answer

Since it doesn't produce a 0, (x + 6 ) is not a factor of the polynomial given.

User Robert Penridge
by
8.0k points
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