1 Answer

Peter Flanagan · Answer 1 · 2023-12-20T03:10:04+0000

The variance of a data set is given by the formula:

$s^2=\sum ^{}_i(x_i-\mu)^2P(x_i)$

Where μ is the mean given by the formula:

$\mu=\sum ^{}_ix_iP(x_i)$

Therefore, in our problem:

$\begin{gathered} \mu=3\cdot0.3+4\cdot0.1+5\cdot0.2+6\cdot0.2+7\cdot0.2=4.9 \\ \Rightarrow\mu=4.9 \end{gathered}$

Then, the variance is:

$\begin{gathered} s^2=0.3(3-4.9)^2+0.1(4-4.9)^2+0.2((5-4.9)^2+(6-4.9)^2+(7-4.9)^2) \\ \Rightarrow s^2=2.29 \end{gathered}$

Thus, the variance is 2.29

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