Question

A jet is goes from 180km/ to 139km/s in. 22 seconds what is its acceleration Vi-Vf-T-A-

Answer 1

Given

Initial velocity,

`v_i=180\text{ km/s}`

Final velocity,

`v_f=139\text{ km/s}`
`Time\text{ taken , t=22 s}`

To find

The acceleration

Step-by-step explanation

Acceleration is the ratio of change in velocity to that of the time taken

Thus,

`\begin{gathered} a=(v_f-v_i)/(t) \\ \Rightarrow a=(180-139)/(22) \\ \Rightarrow a=1.86\text{ km/s}^2 \end{gathered}`

Conclusion

The acceleration is

`1.86\text{ km./s}^2`