Answer:
A. Distance KL = 7.36 m
B. Height ML = 4.25 m
C. The maximum height is 6.96 m
Explanation:
A. Determination of distance KL
Hypothenus = KM = 8.5 m
Angle θ = 30°
Adjacent = KL =?
Cos θ = Adjacent / Hypothenus
Cos 30 = KL / 8.5
0.866 = KL / 8.5
Cross multiply
KL = 0.866 × 8.5
KL = 7.36 m
Thus, the distance is 7.36 m
B. Determination of height (ML)
Hypothenus = KM = 8.5 m
Angle θ = 30°
Opposite = ML =?
Sine θ = Opposite /Hypothenus
Sine 30 = ML /8.5
0.5 = ML / 8.5
Cross multiply
ML = 0.5 × 8.5
ML = 4.25 m
Thus, the height is 4.25 m
C. Determination of the maximum height.
Hypothenus = KM = 8.5 m
Angle θ = 55°
Opposite = ML =?
Sine θ = Opposite /Hypothenus
Sine 55 = ML /8.5
0.8192 = ML / 8.5
Cross multiply
ML = 0.8192 × 8.5
ML = 6.96 m
Thus, the maximum height is 6.96 m