Question

A population of 430 animals increases at an annual rate of 19%. Find the number of animals present after 5 years. Round your answer to the nearest whole number.

Answer 1

19% of 430 is 81.7.

81.7 x 5 = 408.5

408.5 + 430 = 838.5

The population of animals present after 5 years is 838.5, but rounded to the nearest whole number would make it 839.

Answer 2

• 1026

Explanation:

• Initial number = 430
• Increase rate = 19% = 1.19 times per year

Number of animals after 5 years:

• 430*1.19^5 = 1026