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Expand (x – 4)^5 using the Binomial Theorem and Pascal’s triangle. Show all necessary steps.

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SOLUTION

The given expression is:


(x-4)^5

Using binomial theorem, the function is expanded as follows:


(x-4)^5=x^5+5(x)^4(-4)^+(5(5-1))/(2!)x^3(-4)^2+(5(5-1)(5-2))/(3!)x^2(-4)^3+(5(5-1)(5-2)(5-3))/(4!)x^(-4)^4+(-4)^5

This gives:


(x-4)^5=x^5-20x^4+160x^3-640x^2+1280x-1024

The pascal triangle is shown:

Using pascal triangle the expansion is shown:


\begin{gathered} (x-4)^5=x^5+5x^4(-4)+10x^3(-4)^2+10x^2(-4)^3+5x(-4)^4+(-4)^5 \\ (x-4)^5=x^5-20x^4+160x^3-640x^2+1280x-1024 \end{gathered}

Expand (x – 4)^5 using the Binomial Theorem and Pascal’s triangle. Show all necessary-example-1
User Weivall
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