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(1)/(2) {x}^(2) + 1 = 2 * - 1Solve the equation

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Solve the system of equations:

4x-2y=10 (1)

y=2x-5 (2)

We can substitute 2 in 1:

4x-2(2x-5)=10

4x-4x+10=10

0=0

Since the solution of the system of equation is 0=0 we can say that it has infinite solutions.

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