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Dean is on top of a 300 m high cliff. He sees Emily in her new sailboat. If dean calculates the angle of depression to the boat to be 25° how far from the base of the cliff is Emily’s boat

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To answer this question we will use the following diagram as reference:

Let d be the distance from the base of the cliff to Emily's boat, then, from the above diagram we can set the following equation:


\tan 25º=(300m)/(d)\text{.}

Then:


d=(300m)/(\tan 25º)\text{.}

Simplifying the above result we get:


d\approx643.35m

Answer:


643.35m

Dean is on top of a 300 m high cliff. He sees Emily in her new sailboat. If dean calculates-example-1
User Ekambaram E
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