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Geometry question - Given: AB and AC are the legs of isosceles triangle ABC, measure of angle 1 = 5x, measure of angle three = 2x + 12. Find measure of angle 2 (reference picture)

Geometry question - Given: AB and AC are the legs of isosceles triangle ABC, measure-example-1
User Ajoseps
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Since triangle, ABC is an isosceles triangle because AB = BC

Then the angles of its base are equal

Since the angles of its bases are <2 and <4, then


m\angle2=m\angle4

Since <3 and <4 are vertically opposite angles

Since the vertically opposite angles are equal in measures, then


m\angle3=m\angle4

Since measure of <3 = 2x + 12, them


m\angle4=m\angle2=2x+12

Since <1 and <2 are linear angles

Since the sum of the measures of the linear angles is 180 degrees, then


m\angle2+m\angle1=180

Since m<1 = 5x, then


\begin{gathered} m\angle1=5x \\ m\angle2=2x+12 \\ 2x+12+5x=180 \end{gathered}

Add the like terms on the left side


\begin{gathered} (2x+5x)+12=180 \\ 7x+12=180 \end{gathered}

Subtract 12 from both sides


\begin{gathered} 7x+12-12=180-12 \\ 7x=168 \end{gathered}

Divide both sides by 7


\begin{gathered} (7x)/(7)=(168)/(7) \\ x=24 \end{gathered}

Then substitute x by 24 in the measure of <2


\begin{gathered} m\angle2=2x+12 \\ m\angle2=2(24)+12 \\ m\angle2=48+12 \\ m\angle2=\mathring{60} \end{gathered}

The measure of angle 2 is 60 degrees

User Gleng
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