We are asked to determine the density of the cork. To do that we will use the following formula:
![D=(m)/(V)](https://img.qammunity.org/2023/formulas/physics/college/lb0ati8kxrgudy1ujo6gs2uwiwx340rhs8.png)
Where:
![\begin{gathered} D=\text{ density} \\ m=\text{ mass} \\ V=\text{ volume} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/pc9fmpb19hz8empn45shqsb3ryb8tye0dy.png)
The volume of the cork is the same as the volume that it displaced of water, therefore, we have:
![V=23.5ml](https://img.qammunity.org/2023/formulas/mathematics/college/b72t8nhk797h967gsiz9k9dbn6bj1coovq.png)
Now, we substitute the values and we get:
![D=(5.7g)/(23.5ml)](https://img.qammunity.org/2023/formulas/mathematics/college/gszk4rw3br0nassjuhdfpu3iiijfow5eoa.png)
Solving the operations:
![D=0.24(g)/(ml)](https://img.qammunity.org/2023/formulas/mathematics/college/v2vaahd2smhb0unu5erdbmi6p3c8umjbpd.png)
Therefore, the density of the cork is 0.24 g/ml.