Given:
![\begin{gathered} x-5y=-9\ldots\ldots(1) \\ 4x+4y=-12\ldots\text{.}\mathrm{}(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/36aedgil6srzdypmgpmlja1ov7jbgzotb5.png)
The given point is (-4,1)
Let's check the ordered pair (-4,1) in the first equation
![\begin{gathered} x-5y=-9 \\ (-4)-5(1)=-9 \\ -4-5=-9 \\ -9=-9 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/thdzegrad8qxg9wqj7at4dch9vyoq6cnz1.png)
Hence, (-4,1) is a solution of the first equation x-5y=-9.
Now, let's check (-4,1) in the second equation.
![\begin{gathered} 4x+4y=-12 \\ 4(-4)+4(1)=-12 \\ -16+4=-12 \\ -12=-12 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/18cr9v602tyj8v3c8x2fqncjft9qsk77ra.png)
So, (-4,1) is a solution of the second equation 4x+4y=-12.
Hence, (-4,1) is a solution of both equation in the system, then it is a solution to the overall system.