Question

A lemming take off from the roof of a building 56m tall and lands 45m from the base. What was the lemming’s initial speed ?

Answer 1

Given data

*The given height of the building h = 56 m

*The distance from the base is d = 45 m

*The value of the acceleration due to gravity is g = 9.8 m/s^2

The formula for the time taken by the lemming is given as

`t=\sqrt[]{(2h)/(g)}`

Substitute the known values in the above expression as

`\begin{gathered} t=\sqrt[]{(2*56)/(9.8)} \\ =3.38\text{ s} \end{gathered}`

The formula for the lemming's initial speed is given as

`v=(d)/(t)`

Substitute the known values in the above expression as

`\begin{gathered} v=(45)/(3.38) \\ =13.3\text{ m/s} \end{gathered}`

Hence, the lemming's initial speed is v = 13.3 m/s